Show that if A, B, C, and D are sets with |A|=|B| and |C|=|D|, then |A×C|=|B×D|

As usual, let’s refresh some definitions we will use to solve this exercise.

Definition: Let A and B be sets. The Cartesian product of A and B, denoted by A × B, is the set of all ordered pairs (a, b), where a ∈ A and b ∈ B. Hence, A × B = {(a, b) | a ∈ A ∧ b ∈ B}.

Definition: The function f is a one-to-one correspondence, or a bijection, if it is both one-to-one and onto. We also say that such a function is bijective.

Definition: The sets A and B have the same cardinality if and only if there is a one-to-one correspondence from A to B. When A and B have the same cardinality, we write |A| = |B|.

All definitions were taken from the textbook Discrete Mathematics and its Applications by Rosen.

If |A|=|B|, then there exists a one-to-one correspondence f from A to B.

Also, if |C|=|D|, then there exists a one-to-one correspondence g from C to D.

From the definition of the cartesian product, we get that:

|AxC| = {(a,c), such that a ∈ A ∧ c ∈ C}

|BxD| = {(b,d), such that b ∈ b ∧ d ∈ D}

Then, the function h(a,c) = (f(a),g(c)), from |AxC| to |BxD| is also a one-to-one correspondence.

Therefore, |A×C|=|B×D|.

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