Show that the relation R = ∅ on a nonempty set S is symmetric and transitive, but not reflexive

Let’s refresh the definitions that are relevant to this exercise.

Definition: “A relation R on a set A is called reflexive if (a, a) ∈ R for every element a ∈ A.”

Definition: “A relation R on a set A is called symmetric if (b, a) ∈ R whenever (a,b) ∈ R, for all a,b ∈ A.

Definition: “A relation R on a set A is called transitive if whenever (a,b)∈R and (b,c)∈R, then (a,c) ∈ R, for all a,b,c ∈ A.”

The definitions above are from the textbook “Discrete Mathematics and its Applications” by Rosen.

Now, let’s solve the exercise.

Let a∈S, (a, a)∉R because of R=∅. Therefore, R is not reflexive.

As per the definition of symmetric relation, if (b, a) ∈ R whenever (a, b) ∈ R, for all a, b ∈ A, then the relation is symmetric. This holds for R==∅. Therefore, R is symmetric.

Similarly, As per the definition of transitive relation, whenever (a,b)∈R and (b,c)∈R, then (a,c) ∈ R, for all a,b,c ∈ A. This condition also holds for R=∅. Therefore, R is transitive.

If this is confusing for you, try to find an ordered pair (x, y) that belongs to R, and then prove that (y, x) does not belong to R.

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